WEBVTT

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so first step is we're going to subtract C from both sides. Okay. And now, where are

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Where are we at? Divide by a. We need to turn the leading coefficient into one, so

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we divide

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both sides by the leading coefficient. Alright, now we've got to complete the

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square. Okay,

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We take this, which is no longer our b value, but it is like our new b value.

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We take that, divide by two, and square it. That becomes (b over two a) squared. We

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could write it like this.

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Or we can leave it like this, either one. This is what we add to both sides: b

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squared over four a squared.

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And I'm going to write on the left side here. You'll see why in a minute. Okay. We

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normally write it just to the right over here.

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If I put it here, you will see. Now this factors. What does this factor to? x plus b

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over two a. It is always this thing divided by two.

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So B over 2A. B over 2A. And then the right side, we're going to need to get a

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common denominator. So the common denominator is going to be 4A squared.

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So this needs a 4A over 4A. That's B squared over 4A squared minus 4AC over 4A

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squared.

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Okay. Now we have something squared equals some number. Is it just a number? What do

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we use next? The square root principle. The something that is squared is plus or

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minus the square root.

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And what? Let's subtract B over 2A. And I put it on the left side.

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Then this denominator simplifies. What does that simplify to?

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Two a. Now we have a common denominator, so we can make one fraction.

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And there it is. Okay. We just derived or proved that all we got to do is know the

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coefficients A, B, and C.

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And all we do is plug it into this formula. And this will give us our two solutions.

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This is what's known as the quadratic formula. The very famous formula. It works for

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every single quadratic equation.

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Okay. So this is called the quadratic formula.

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In fact, we never have to use completing the square again. We did it for all

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quadratics. Instead of going through the whole thing, we plug the numbers a, b, and

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c into here and simplify.

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But whenever you want to solve by factoring, you do not have to do this. If the

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quadratic can be solved by factoring, we usually do that if it is quick. If it is

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not quick and you cannot figure it out, we go to the quadratic formula.

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Okay. Before we use the quadratic formula, what do we have to do? Put it in the

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standard form. It's called Ax squared plus Bx plus C equals zero. So we have to

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subtract 3x from both sides.

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Okay.

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x equals negative b plus or minus the square root of b squared minus four a c, all

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over two a.

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We have negative b, the negative of negative three, plus or minus the square root of

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b squared: negative three squared minus four times a, which is one, times c, which

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is negative four, all over two times one.

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And now we simplify.

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Four times negative four is negative sixteen, so subtracting negative sixteen gives

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plus sixteen, all over two.

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And so again, this is two separate equations. Well, I'm going to write one more

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first. 3 plus or minus 5 over 2, which is x is 3 plus 5 over 2, or x is 3 minus 5

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over 2.

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Okay.

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Our solutions are integers. That tells us it could have been solved by factoring. If

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the thing inside the square root is not a perfect square, it could be solved by the

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quadratic formula or completing the square.

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This makes sense. Okay. That's the first one using a formula. We got to memorize the

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formula. This is very important.

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One way to memorize it is by this song.

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x equals negative b plus or minus the square root of b squared minus four a c, all

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over two a.

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Okay, now with your pen in hand on your paper, we're going to say.

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We are going to sing and write the formula as we go.

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Here we go.

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x equals negative b plus or minus the square root of b squared minus four a c, all

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over two a.

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This is already in standard form. What is my a?

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Two. b?

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Negative five. c?

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So first let's write it with the letters in there and then we'll write with the

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numbers plugged in. So here we go.

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Okay.

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Can we simplify the square root of thirty-three?

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And we're done. That's it. These are this is my solution set.

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If we ever get this, we're going to learn this later.

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What was my original equation? Two x squared.

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It tells us this does factor.

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The two zeros.

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We subtract these numbers: five minus square root thirty-three, over four.

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Five plus square root thirty-three, over four.

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Except we're missing the leading coefficient. So we have the two out here.

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So that's what this thing factors to two times X minus one of the solutions times X

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minus the other solution.

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It should make sense, right? You plug in a solution right here. That same number

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minus that number zero.

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And the other number plus.

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Five plus square root thirty-three, over four, minus that number.

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And that's it. So every polynomial does factor to exactly the leading coefficient,

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the A, times X minus one of the solutions times X minus the other solutions.

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OK, let's see some other. Let's try some more.

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This quadratic has a common factor in all three terms.

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What is the common factor? Two. But I want to show you what happens if we do this.

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We could divide both sides by two and make all the numbers smaller and it would be

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easier.

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Let's see what happens when we use quadratic formula when there is a common factor

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in here.

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Negative b. What is b?

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Negative four plus or minus the square root of b squared minus four a c, all over

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two a.

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Hopefully we go right to that. You do not even have to list a, b, and c: negative b

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plus or minus the square root of b

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Square minus four times A C.

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And now let's simplify.

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What is that plus sixteen?

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OK, this is the two solutions. However, we can simplify this. What is the square

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root of thirty two simplified to?

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Four square root two.

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Now both of these have a common factor of four.

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So we can either divide both of these by four.

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It would be negative four over four, plus or minus four square root two over four.

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We get negative one plus or minus square root two.

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The other option is you factor out a four.

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And those simplify.

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Negative one plus or minus square root two.

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So if there is a common factor, you can still leave it in there, except you're

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definitely going to have to simplify.

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And there will be a common thing that factors out.

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OK, let's try another one.

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x equals negative b plus or minus the square root of b squared minus four a c, all

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over two a.

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What is B?

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Negative ten.

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Negative ten.

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Negative ten squared.

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Negative ten.

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So our two solutions are ten plus zero over two and ten minus zero over two.

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OK, so we really only have one solution.

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Whenever we end up with just one solution or in other words, when this thing is

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zero, it's the only time you get one solution.

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It does tell us that this is a perfect squared trinomial.

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OK, this factors to X minus five times X minus five, which is X minus five squared.

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Whenever the thing inside the radical of the quadratic formula is zero,

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We're only going to get one solution.

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And it tells us the quadratic is a perfect square trinomial.

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Now let's see what happens.

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OK.

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Sometimes b squared minus four a c is a negative number.

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So what does that tell us?

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This is not a real number.

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OK, so there are no real solutions.

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Does it have a solution set? Yes. Yes, and it is the empty set.

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OK, so as soon as B squared minus four AC is a negative, there's no real solution.

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Later on, we will learn something very interesting, and we will not be done here.

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But right now we will be done.

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OK, so let's look one more time at this thing.

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OK, this radicand of the quadratic formula is called the discriminant.

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OK, so this number classifies our solutions.

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OK, if B squared minus four AC is greater than zero, what does that tell us?

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There's two real solutions.

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If the discriminant B squared minus four AC is equal to zero, what does that tell

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us?

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There's one real solution.

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It also tells us it can be factored: the quadratic is a perfect square trinomial.

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And if B squared minus four AC is less than zero, what does that tell us?

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There are no real solutions.

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OK, and then we tell this even more.

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If B squared minus four AC is a perfect square.

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What does that tell us?

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What's that?

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The solutions are integers?

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Not necessarily because we have to divide at least by two.

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It might not be an integer, but the square root of the perfect square.

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The square root will be an integer.

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Well, it could be.

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Yeah, but it tells us we're going to have two.

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So the square root will simplify since it's a perfect square.

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So we have two rational solutions.

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What's a rational number?

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Any number that can be written as the ratio of two integers.

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OK, if B squared minus four AC is not a perfect square.

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Then what?

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Then there are two irrational solutions.

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And your answer is going to have a square root.

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If we want to approximate the solution, we need a calculator to type in the square

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root, then add negative b and divide by two a.

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OK, so the discriminant tells a lot.

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If it's positive, two real.

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If it's zero, there's one real.

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And the quadratic is a perfect square trinomial.

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If the discriminant is negative, there's no real solutions.

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If it's a perfect square, there's two rational.

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And if it's not a perfect square, there's two irrational.

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If b squared minus four a c is a perfect square, it tells us we could have solved by

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factoring.
