WEBVTT



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Let us factor this expression. To factor means to write it as a product.

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What do we call this polynomial?

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It is a quadratic binomial.

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Is it missing the quadratic, linear, or constant term?

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It is missing the linear term.

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We could write it like this.

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We need a factor pair whose product is negative 49 and whose sum is zero.

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The pair is negative seven and positive seven.

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plus seven.

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That's plus seven.

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That gives x minus seven and x plus seven.

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Yes. Easy peasy. Wow.

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Okay.

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Do we need to write this step? Definitely not.

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We need two numbers whose product is negative five and whose sum is zero.

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to be negative 5 and add to be 0.

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Maybe it's not.

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Maybe it's not.

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Definitely not.

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What did we...

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Somebody said... What did somebody say?

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What did you say?

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Uh...

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Rad...

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Use square root of five and negative square root of five.

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I'm gonna be a bad man.

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Uh...

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Rad pod and negative red pod.

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Those numbers multiply to negative five and add to zero.

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These factors are not integers, but they are valid real numbers.

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Integers, but they are two numbers that multiplied to be negative five and add to be

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zero

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The factorization is x minus square root of five times x plus square root of five.

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Should we check and see if it works?

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Multiply to check: the middle terms cancel, and the product is x squared minus five.

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Oops, I normally do it here.

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here. And we get minus 5

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at 0

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and that's it.

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Okay.

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Can two real numbers multiply to 36 and add to zero?

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It's not 6 and negative 6.

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Why not?

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Yeah, that does not multiply to be 36.

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Are there any?

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There are none.

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They would need the same sign to have a positive product, so their sum cannot be

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zero.

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Two positives add together, never will be zero. Two negatives add together will

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never be zero.

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Therefore this expression does not factor over the real numbers.

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This is called a sum of squares.

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A sum of squares does not factor over the real numbers.

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Okay.

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The earlier examples are differences of squares.

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What do we call this?

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The difference of squares.

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Difference.

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Oh, squares.

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Okay.

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A difference of two squares always factors.

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A squared minus b squared factors as a minus b times a plus b.

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always factors to what?

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A plus B times

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A minus B.

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and that order doesn't matter.

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Let's call the

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difference of squares.

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Write x squared minus one hundred as x squared minus ten squared.

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It factors as x minus ten times x plus ten.

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OK.

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Rather than multiplying everything out, recognize the square terms.

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and then look for two factors and...

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Too complicated.

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It's very easy.

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Four x squared is the square of two x.

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2x.

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Thirty-six is the square of six.

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Six.

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This is a difference of squares.

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It factors as two x minus six times two x plus six.

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2x minus six.

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That's 2x plus six.

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Done.

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Let's try another one.

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This expression is a difference of squares.

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One hundred x squared is the square of ten x, and eighty-one is the square of nine.

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81 is 9.

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It factors as ten x minus nine times ten x plus nine.

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plus 9

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Uh...

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The square roots are four x and five y.

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So the factors are four x minus five y and four x plus five y.

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Done.

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Okay, let's try another one.

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This is also a difference of squares.

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The square root of this?

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The square root of twenty-five x squared is five x.

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What's the square root of this?

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The square root of seven stays square root of seven, giving conjugate factors.

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This is a fourth-degree binomial rather than a quadratic binomial.

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What would this be?

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4th degree bound.

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However, it is still a difference of squares.

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The square root of x to the fourth is x squared, and the square root of sixteen is

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four.

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x squared.

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What squared is 16?

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4.

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4. This is going to be

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First factor as x squared minus four times x squared plus four.

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squared plus 4.

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We are not finished because x squared minus four is another difference of squares.

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Factor x squared minus four again.

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difference of squares.

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The complete factorization is x minus two times x plus two times x squared plus

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four.

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The sum of squares x squared plus four is prime over the real numbers.

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Difference of squares lets us factor higher-degree polynomials.

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And it's going to be very useful when we learn something else later.

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But let's try one more.

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This is another difference of squares.

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What square is x need?

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The square root of x to the eighth is x to the fourth, and the square root of one is

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one.

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And we have two fourth degree polynomials. Is one of the two difference the squares?

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Factor x to the fourth minus one again as x squared minus one times x squared plus

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one.

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We are not done because x squared minus one is another difference of squares.

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No. We got another

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difference of squares.

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Now the expression is completely factored.

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What's that?

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The result is the product of four binomials, and their order does not matter.

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4 binomials. The order does not matter.

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Because the multiplication is commuted. Sorry, let's do one more.

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First factor out the greatest common factor.

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Factor out what?

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Always remove the greatest common factor before applying another factoring method.

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What is the greatest common factor?

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The greatest common factor is ten x cubed.

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The remaining quadratic binomial is a difference of squares.

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Okay, we good?
