WEBVTT

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Is this a quadratic function? Yes. How can we tell? We multiply this out. The

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x times the x becomes the x squared. Definitely quadratic. You multiply any two

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linear, you

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get a quadratic. You multiply three linear, what do you get? So our goal is to graph

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this

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function just like we were graphing the quadratic functions. This is non-standard

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form. Is it

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in vertex form? No. Uh-oh. So how are we going to get it in one of those forms? We

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just got

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Multiply it out: x squared plus three x minus x minus three.

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Now it is in standard form. Standard form tells us two things. What are they?

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The y-intercept. We definitely know the y-intercept. And whether it

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opens up or opens down, which one is this? Open up because what's positive? Leading

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coefficient.

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Okay, so if we want to find

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vertex form, how are we going to do that? You could complete the square. The better

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way is to know the vertex is

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always at negative b over 2a comma f of negative b over 2a. Negative b over 2a is,

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what is b? Is 2. And a is 1.

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So that is negative one. That is the x-coordinate of the vertex.

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And how do we find the y coordinate? Plug it in to the function.

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Oh, no, that's right. I'm sorry. I got confused. Negative 4. We agree? Yes. Okay,

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sorry.

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So that is the y coordinate of the vertex.

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So what is our vertex form? The leading coefficient is one.

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Times x minus this number, which is x plus 1 squared minus 4.

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So the vertex (negative one, negative four) is right there. To graph it, follow the

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pattern: over one, up one;

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over two, up four.

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I'm just doing that because it's on the wrong side of the pattern.

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Over 1 up 1, over 2 up 1, 2, 3, 4. 1, 2, 3, up 9. Up here.

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That's going to be the right hand side. And how do we get the left hand side?

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On the other side. According to the axis of symmetry, which goes right through the

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vertex.

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And then we draw a nice curve.

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What are the x-intercepts?

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Negative three and one.

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Going back to the original quadratic.

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How can we look at that and tell the x-intercepts?

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Uh, we could use a zero product property.

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But it is simply the opposite of that number and the opposite of that number. Why is

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that?

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Yeah, right. We plug in the opposite of negative 1, which is 1.

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And you get 0 times whatever. It doesn't matter. It's 0.

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And the opposite of 3. So we plug in negative 3 plus 3. We get 0 times whatever.

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It's 0.

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Okay. So this is a special form.

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And it tells us something right away. What form is this? Oh, can anyone take this?

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Factored form, because the polynomial is factored.

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Okay. So this is called factored form.

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Okay. And what does it tell you? Those are the x-intercepts.

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Also known as zeros. I'll define that for you in a minute.

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Okay. If we have the x-intercepts

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without doing this negative b over 2a, how can we use the x-intercepts to figure out

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the x-coordinate

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of the vertex?

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We find the mean of these two?

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We find the mean, the average of the two, exactly halfway. Okay. Why is it exactly

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halfway?

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Because they are split about the axis of symmetry.

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Any two points on this parabola on the same horizontal line are symmetric.

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Symmetric ordered pairs. So if you find two such points,

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especially when they, like let's say they landed right here and here or something,

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where we couldn't know the zeros, we'll just go halfway. Exactly as the axis of

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symmetry,

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which is the x-coordinate of the vertex. So...

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So that's an alternative way,

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To find this value. And once we have that value, we just plug it into this function

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or this function to figure it out, the y-coordinate.

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So, right, if we plug in what's halfway? Negative one.

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Negative one minus one times negative one plus three, which is

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negative two times two, which is our negative four, our y-coordinate of the vertex.

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Okay, so that is factored form. So factored form

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Factored form is f of x equals the leading coefficient a, the same a as in vertex

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and standard forms, times x minus

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z one, times x minus z two, where

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z one and z two are the zeros, the x-coordinates of the intercepts.

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Okay, let me define the word zero for it.

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a zero

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of a function

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is an x value

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that makes

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the y-value, or function value,

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equal to zero, the number zero.

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It is the same as the x-coordinate of an x-intercept. Sometimes

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we could say the x-intercepts are negative three and one, or you can actually talk

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about the ordered pair.

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Typically, the x-intercept is actually an ordered pair, but we often just refer to

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it as a number.

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But these would be the zeros of the function. Zeros are numbers, x values that make

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the y value or

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the function value zero.

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What form is this in? Factored form.

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Okay, so what do we instantly know?

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What do we know from this form?

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The zeros.

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Zeros.

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Okay, also known as the x-intercepts.

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The zeros are the opposite of that number and the opposite of that number, two,

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negative four.

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Two, negative four.

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Okay.

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And then the vertex, the x-coordinate of the vertex,

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of the vertex is...

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Right, it's z one plus z two divided by two, which is two plus negative four divided

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by two.

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Here that is negative two over two, which is negative one.

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So we know this is the axis of symmetry.

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And then how would we find the y-coordinate of the vertex?

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Plug it in. We don't even need to multiply this out.

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So f of negative one is two times (negative one minus two) times (negative one plus

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four),

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which is two times negative three times three, which is

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negative eighteen. Uh-oh. So the only problem with this is way off my graph.

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Way down here at negative eighteen. Sorry, negative one comma negative eighteen.

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It's going to be a little harder to graph because I don't have a graph paper right

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here.

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But we would follow our pattern over... We're not going to go over one up one. Where

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are we going to go?

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Over one, up two. The parent offsets are (0,0), (1,1), (2,4), and (3,9).

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Our new pattern, instead of x and x squared, uses x and two x squared.

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Multiply those vertical offsets by two.

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Two, eight, eighteen.

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So I go over one up two.

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Over three up... Sorry, over two up eight.

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It's going to be right here at ten. I didn't draw this very well.

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Negative ten. And over three, up eighteen reaches the zeros right there.

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And then we got some symmetric points.

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We get a nice smooth curve.

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Okay.

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Okay. So what is the...

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What is the vertex form?

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Two...

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What was the vertex?

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Was it negative one...

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Negative eighteen.

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It is two times (x plus one) squared, minus eighteen.

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Okay. And then how would we get standard forms?

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We could either multiply this out, multiply it by two, and then subtract 18, or it's

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probably

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easier right here: two times (x squared plus four x minus two x minus eight).

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Which form should we... Let's go with the factored form first.

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Factored form is the leading coefficient times x minus one zero, times

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x minus the other zero. What are the zeros?

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Negative one, negative three.

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Negative one and negative three. So we have x minus negative one, or x plus one,

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and x minus negative three, or x plus three. How do we determine the leading

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coefficient from the graph?

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You start at the vertex. We go one to the right.

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And since we go down two, we know the leading coefficient is negative two.

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We can go right to the vertex form.

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The leading coefficient is negative two, times

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(x plus two) squared, plus two. Lots of twos.

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And then standard form. We know it's going to be

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a coefficient times x squared, plus or minus a coefficient times x.

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We do know the y-intercept, which is what? Negative six.

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But you need to multiply this out. So we got x squared

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negative two times x squared plus three x plus x plus three.

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Three x plus x is four x. Distributing negative two gives negative eight x and

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negative six.

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And that is standard form.

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What two things do we know?

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It opens upward because the leading coefficient is positive, and its y-intercept is

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negative one.

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How can we get this into factored form? One option is to factor it.

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Does it factor?

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The integer factors are one and negative one; those do not add to two.

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So how are we going to factor it?

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Find the zeros. We need to determine the zeros.

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How do we figure out the zeros

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Okay, we could do that, but I have a feeling

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They will not be obvious integers. This is just a rough sketch.

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Okay to find any zeros of a function

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You set the function equal to zero

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So we go zero equals x squared plus 2x minus 1

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And now we have a quadratic equation in one variable

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It cannot be solved by integer factoring. What is the next option?

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Use the quadratic formula.

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We sing it all together. Yes, we ready. Yes

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Negative b,

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the square root of b squared minus four a c.

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Negative two plus or minus the square root of two squared minus four times one times

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negative 1

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All over two.

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And

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The square root of eight is two square roots of two.

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Either factor out a two, or

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divide negative two by two and divide plus or minus two square roots of two by two.

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Those are the zeros, the x-coordinates of the intercepts.

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Oh

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So how do we put it in factored form?

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Well, do we know the leading coefficient which is

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one

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These are two numbers: negative one plus the square root of two

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and

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and negative one minus the square root of two.

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Factored form is

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One times x minus

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(negative one plus the square root of two),

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times x minus (negative one minus the square root of two).

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Distribute the signs to simplify.

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Get x

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plus one minus the square root of two;

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X plus 1

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Plus

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the square root of two.

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So

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So where the heck are those two numbers on the graph

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We'll get there in a second

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What is the square root of two approximately?

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One point something

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Let us use about

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One point four ish

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so negative one plus one point four and

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negative one minus one point four is

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Point four and negative two point four

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So point four and negative two point four

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Okay, the axis of symmetry is halfway

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Okay, which is the average of these two numbers

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Negative one plus the square root of two, plus negative one minus

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the square root of two, all over two.

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The two radical terms cancel to zero.

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So we get negative 2 over 2

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negative 1

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Okay, this is our axis of symmetry

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To get the y-coordinate of the vertex,

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evaluate f at negative one.

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F of negative one is (negative one) squared plus two times

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negative one,

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minus one,

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which is

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negative two.

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Follow our pattern

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Let's put it in vertex form

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The leading coefficient is one. What was the

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x-coordinate of the vertex? Negative one, so use (x plus one) squared,

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minus two.

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Okay

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So

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Almost every

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quadratic we have discussed can be written in all three forms. Each form tells us

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something different.

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We can convert to all the forms

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The only time

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We're not going to be able to write in factored form

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Okay

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Okay is this

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Why can we not write this in factored form

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If there are no x intercepts

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It cannot be factored into real linear factors.

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We know this equation, right?

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Or this function would be

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(x minus three) squared plus two.

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So how can you tell

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Yeah, if you have the graph it's obvious

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if the

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It opens up and above the x-axis

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It has no x-intercepts. Likewise, a downward-opening parabola with a negative

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maximum has no

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x-intercepts.

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What if we only have standard form?

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This is x squared minus 6x

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plus

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11

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If we substitute into the

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Quadratic formula

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You're gonna get negative negative 6 plus or minus

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36 minus 4 times 1 times 11

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Thirty-six minus forty-four. What is the radicand?

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Sorry, what's the discriminant?

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negative

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Negative eight, which means there are no real

00:27:52.230 --> 00:27:58.050
solutions to f of x equals zero: no real zeros and no x-intercepts.

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It cannot be written as a product of real linear factors.
